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> What happens if you have conflicting declarations in different procs?
proc one () {
global int $foo = 3;
print ("\n" + $foo );
$foo = 1;
print (" " + $foo);
}
proc two () {
global int $foo = 6;
print ("\n" + $foo );
$foo = 7;
print (" " + $foo);
}
one();
two();
prints
6 1
1 7
Which is lovely
There's stuff above here
Generated at 14:02 on 01 Jul 2004 by mariachi 0.52