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On Fri, Dec 22, 2006 at 09:16:08AM -0600, Peter da Silva wrote:
> On Dec 22, 2006, at 8:10 AM, Abigail wrote:
> >In Perl6:
> >
> > print sqrt(9) + 7; # Prints 10.
> > print sqrt (9) + 7; # Prints 4.
>=20
> Holy Mary's Abscessed Teeth.
>=20
> Is this because whitespace is significant in the parse tree, or because=
=20
> sqrt( is a token? Or don't I want to know?
Worse.
The space influences precedence.
Fully parenthesized,=20
the former is read as: ((sqrt(9)) + (7))
the latter is read as: (sqrt((9) + (7)))
Now, the other example I gave (%hash {code} vs %hash{code}) is a parsing
issue. Any parenthesized block preceeded by a space is a coderef that is
executed directly. More or less a short hand for 'sub {code} -> ()'.
But without the space, well, then it can be an index in a hash.
Now, you might wonder what was gained by having this monster. It enables
you to leave of the parenthesis in an if statement. Perl goes from a
formfree language to a language with syntactically whitespace for the
benefit of making parenthesis around a conditional optional.
Woopy.
Abigail
(So, what's 'grep {/foo/} @bar;' meaning in perl6?)
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